Linear run
Moderators: silvia, selimgunay, Moderators
Linear run
Is the linear case supposed to converge at 1 iteration? Why 2 iterations are needed to reach the convergence?
I'm using "test NormDispIncr 1e-04 50 1".
Thanks.
Jinchi
I'm using "test NormDispIncr 1e-04 50 1".
Thanks.
Jinchi
Re: Linear run
What do you mean by "linear case"?
Re: Linear run
Linear run. e.g., a mesh of solid elements where the material is linear elastic isotropic.
Re: Linear run
Below is the sample screen output:
CTestNormDispIncr::test() - iteration: 1 current Norm: 0.00022683 (max: 0.0001, Norm deltaR: 20435.1)
CTestNormDispIncr::test() - iteration: 2 current Norm: 4.27053e-007 (max: 0.0001, Norm deltaR: 20435.1)
CTestNormDispIncr::test() - iteration: 1 current Norm: 0.00022683 (max: 0.0001, Norm deltaR: 20448.2)
CTestNormDispIncr::test() - iteration: 2 current Norm: 4.2707e-007 (max: 0.0001, Norm deltaR: 20448.2)
CTestNormDispIncr::test() - iteration: 1 current Norm: 0.00022683 (max: 0.0001, Norm deltaR: 20461.3)
CTestNormDispIncr::test() - iteration: 2 current Norm: 4.2707e-007 (max: 0.0001, Norm deltaR: 20461.3)
CTestNormDispIncr::test() - iteration: 1 current Norm: 0.00022683 (max: 0.0001, Norm deltaR: 20474.4)
CTestNormDispIncr::test() - iteration: 2 current Norm: 4.2707e-007 (max: 0.0001, Norm deltaR: 20474.4)
CTestNormDispIncr::test() - iteration: 1 current Norm: 0.00022683 (max: 0.0001, Norm deltaR: 20487.7)
CTestNormDispIncr::test() - iteration: 2 current Norm: 4.2707e-007 (max: 0.0001, Norm deltaR: 20487.7)
CTestNormDispIncr::test() - iteration: 1 current Norm: 0.00022683 (max: 0.0001, Norm deltaR: 20435.1)
CTestNormDispIncr::test() - iteration: 2 current Norm: 4.27053e-007 (max: 0.0001, Norm deltaR: 20435.1)
CTestNormDispIncr::test() - iteration: 1 current Norm: 0.00022683 (max: 0.0001, Norm deltaR: 20448.2)
CTestNormDispIncr::test() - iteration: 2 current Norm: 4.2707e-007 (max: 0.0001, Norm deltaR: 20448.2)
CTestNormDispIncr::test() - iteration: 1 current Norm: 0.00022683 (max: 0.0001, Norm deltaR: 20461.3)
CTestNormDispIncr::test() - iteration: 2 current Norm: 4.2707e-007 (max: 0.0001, Norm deltaR: 20461.3)
CTestNormDispIncr::test() - iteration: 1 current Norm: 0.00022683 (max: 0.0001, Norm deltaR: 20474.4)
CTestNormDispIncr::test() - iteration: 2 current Norm: 4.2707e-007 (max: 0.0001, Norm deltaR: 20474.4)
CTestNormDispIncr::test() - iteration: 1 current Norm: 0.00022683 (max: 0.0001, Norm deltaR: 20487.7)
CTestNormDispIncr::test() - iteration: 2 current Norm: 4.2707e-007 (max: 0.0001, Norm deltaR: 20487.7)
Re: Linear run
If you use linear algorithm you will get solution in one step, but if you use any other algorithm it may happen that you need more than one step to converge.
Re: Linear run
Thank you very much Vesna.