shear wall
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shear wall
hello
I have a problem in exampl wall 01
how determined $y and $z in fiber commond and why $z in all strips is 1.
please show on shape of this wall
thanks.
. WALL01-EXAMPLE
The following example creates a wall model formed with 8 elements, where each element consists of 8 strips. The model represents a wall with a constant axial load and a variable lateral load applied at the top. It is considered fixed to the bottom and the lateral load is incremented trough prescribed displacements at wall top up to 1.6 in.
wipe; model basic -ndm 2 -ndf 3
set tolAx 1.0e-3; set iterAx 100;
set tolLatNew 1.0e-6; set iterLatNew 100;
set tolLatIni 1.0e-5; set iterLatIni 1000;
set dUi 0.02; # Displacement increment
set maxU 1.6; # Max. Displacement
#concrete parameters
set fc -6.21; set eo -0.0021; set r 2.91;
set k 1.36; set alphaC 0.32; set fcr 0.294;
set ecr 0.00008; set b 0.4; set alphaT 0.08;
set fcc -6.91; set ecc -0.0038; set rcc 1.88;
#steel parameters
set fyRed 59.15; set by 0.02; set Ry 1.564;
set roy 0.00327; set fyBRed 57.33; set byB 0.02;
set RyB 25.0; set royB 0.0293; set fxRed 59.15;
set bx 0.02; set Rx 1.564; set rox 0.00327;
#concrete (confined and unconfined)
uniaxialMaterial Concrete06 1 $fcc $ecc $rcc 1 $alphaC $fcr $ecr $b $alphaT;
uniaxialMaterial Concrete06 2 $fc $eo $r $k $alphaC $fcr $ecr $b $alphaT;
# steel (bound., web and horiz. reinforcement)
set E 29000.0;
uniaxialMaterial Steel02 1003 $fyBRed $E $byB $RyB 0.9 0.1 0 0.1 0 0.1 ;
uniaxialMaterial Steel02 1004 $fyRed $E $by $Ry 0.9 0.1 0 0.1 0 0.1 ;
uniaxialMaterial Steel02 1005 $fxRed $E $bx $Rx 0.9 0.1 0 0.1 0 0.1 ;
# Define cross-section
set t1 6.0; set NStrip1 2; # thickness 1
set t2 4.0; set NStrip2 4; # thickness 2
set t3 6.0; set NStrip3 2; # thickness 3
geomTransf LinearInt 1
set np 1; # int. points
set C 0.4; # center of rotation
#section definition
section FiberInt 2 -NStrip $NStrip1 $t1 $NStrip2 $t2 $NStrip3 $t3 {
#vertical fibers
fiber -23 1 10 1; fiber -23 1 5 2; fiber -23 1 0.3 1003;
fiber -19 1 10 1; fiber -19 1 5 2; fiber -19 1 0.3 1003;
fiber -14 1 33 2; fiber -14 1 0.1 1004;
fiber -6 1 33 2; fiber -6 1 0.1 1004;
fiber 6 1 33 2; fiber 6 1 0.1 1004;
fiber 14 1 33 2; fiber 14 1 0.1 1004;
fiber 19 1 10 1; fiber 19 1 5 2; fiber 19 1 0.3 1003;
fiber 23 1 10 1; fiber 23 1 5 2; fiber 23 1 0.3 1003;
#horiz. reinf.
Hfiber 0 0 0.2 1005;
}
#nodes
set n 8
node 1 0 0.0; node 2 0 160; node 3 0 20; node 4 0 40;
node 5 0 60; node 6 0 80; node 7 0 100; node 8 0 120; node 9 0 140;
#element definition
element dispBeamColumnInt 1 1 3 $np 2 1 $C
element dispBeamColumnInt 2 3 4 $np 2 1 $C
element dispBeamColumnInt 3 4 5 $np 2 1 $C
element dispBeamColumnInt 4 5 6 $np 2 1 $C
element dispBeamColumnInt 5 6 7 $np 2 1 $C
element dispBeamColumnInt 6 7 8 $np 2 1 $C
element dispBeamColumnInt 7 8 9 $np 2 1 $C
element dispBeamColumnInt 8 9 2 $np 2 1 $C
fix 1 1 1 1
# Set axial load
pattern Plain 1 Constant {
load 2 0.0 -85 0.0
}
I have a problem in exampl wall 01
how determined $y and $z in fiber commond and why $z in all strips is 1.
please show on shape of this wall
thanks.
. WALL01-EXAMPLE
The following example creates a wall model formed with 8 elements, where each element consists of 8 strips. The model represents a wall with a constant axial load and a variable lateral load applied at the top. It is considered fixed to the bottom and the lateral load is incremented trough prescribed displacements at wall top up to 1.6 in.
wipe; model basic -ndm 2 -ndf 3
set tolAx 1.0e-3; set iterAx 100;
set tolLatNew 1.0e-6; set iterLatNew 100;
set tolLatIni 1.0e-5; set iterLatIni 1000;
set dUi 0.02; # Displacement increment
set maxU 1.6; # Max. Displacement
#concrete parameters
set fc -6.21; set eo -0.0021; set r 2.91;
set k 1.36; set alphaC 0.32; set fcr 0.294;
set ecr 0.00008; set b 0.4; set alphaT 0.08;
set fcc -6.91; set ecc -0.0038; set rcc 1.88;
#steel parameters
set fyRed 59.15; set by 0.02; set Ry 1.564;
set roy 0.00327; set fyBRed 57.33; set byB 0.02;
set RyB 25.0; set royB 0.0293; set fxRed 59.15;
set bx 0.02; set Rx 1.564; set rox 0.00327;
#concrete (confined and unconfined)
uniaxialMaterial Concrete06 1 $fcc $ecc $rcc 1 $alphaC $fcr $ecr $b $alphaT;
uniaxialMaterial Concrete06 2 $fc $eo $r $k $alphaC $fcr $ecr $b $alphaT;
# steel (bound., web and horiz. reinforcement)
set E 29000.0;
uniaxialMaterial Steel02 1003 $fyBRed $E $byB $RyB 0.9 0.1 0 0.1 0 0.1 ;
uniaxialMaterial Steel02 1004 $fyRed $E $by $Ry 0.9 0.1 0 0.1 0 0.1 ;
uniaxialMaterial Steel02 1005 $fxRed $E $bx $Rx 0.9 0.1 0 0.1 0 0.1 ;
# Define cross-section
set t1 6.0; set NStrip1 2; # thickness 1
set t2 4.0; set NStrip2 4; # thickness 2
set t3 6.0; set NStrip3 2; # thickness 3
geomTransf LinearInt 1
set np 1; # int. points
set C 0.4; # center of rotation
#section definition
section FiberInt 2 -NStrip $NStrip1 $t1 $NStrip2 $t2 $NStrip3 $t3 {
#vertical fibers
fiber -23 1 10 1; fiber -23 1 5 2; fiber -23 1 0.3 1003;
fiber -19 1 10 1; fiber -19 1 5 2; fiber -19 1 0.3 1003;
fiber -14 1 33 2; fiber -14 1 0.1 1004;
fiber -6 1 33 2; fiber -6 1 0.1 1004;
fiber 6 1 33 2; fiber 6 1 0.1 1004;
fiber 14 1 33 2; fiber 14 1 0.1 1004;
fiber 19 1 10 1; fiber 19 1 5 2; fiber 19 1 0.3 1003;
fiber 23 1 10 1; fiber 23 1 5 2; fiber 23 1 0.3 1003;
#horiz. reinf.
Hfiber 0 0 0.2 1005;
}
#nodes
set n 8
node 1 0 0.0; node 2 0 160; node 3 0 20; node 4 0 40;
node 5 0 60; node 6 0 80; node 7 0 100; node 8 0 120; node 9 0 140;
#element definition
element dispBeamColumnInt 1 1 3 $np 2 1 $C
element dispBeamColumnInt 2 3 4 $np 2 1 $C
element dispBeamColumnInt 3 4 5 $np 2 1 $C
element dispBeamColumnInt 4 5 6 $np 2 1 $C
element dispBeamColumnInt 5 6 7 $np 2 1 $C
element dispBeamColumnInt 6 7 8 $np 2 1 $C
element dispBeamColumnInt 7 8 9 $np 2 1 $C
element dispBeamColumnInt 8 9 2 $np 2 1 $C
fix 1 1 1 1
# Set axial load
pattern Plain 1 Constant {
load 2 0.0 -85 0.0
}
Re: shear wall
Based on the command manual page for this shear wall I would think that $y and $z are the coordinates of the fiber centroid in the local coordinate system. Origin of the local coordinate system shall be at the wall cross-section centerline and local y axis should go along the width of the wall.
Value of 1 for $z of all fibers looks like an error to me.
Value of 1 for $z of all fibers looks like an error to me.
Re: shear wall
The geometric transfer can be seen here http://opensees.berkeley.edu/wiki/index ... sformation but as to the $z location it is in the document that for some cases specifying the centroid of the fiber @ reinforcement could yield more accurate results so I guess that's what's going on in Frank's example. I'm having more trouble trying to get this element to work with linear materials than non-linear which seems odd to me.
Re: shear wall
In fact, I also have some problem in simulating the shear wall with the CONCRETE06,for several parameters are out of my determination, such as alpha1,b and alpha2. Do you know how to decide them for the model ?
Re: shear wall
I never used this material. I guess that by reading the referenced papers you will be able to figure out the reasonable values of the three parameters you just mentioned.
Re: shear wall
Hello I have a problem.
I search this flowchart in opensees source code:
[IMG]http://i62.tinypic.com/s60vma.jpg[/IMG]
Can you help me?
I search this flowchart in opensees source code:
[IMG]http://i62.tinypic.com/s60vma.jpg[/IMG]
Can you help me?