Hello engineers
I have a question about simple connection between beams and columns. Lets say I have a frame with 2 bays(spans). As I show below, i,j and k are the places for the columns which are connected with beam 1 and beam2. I want to have a beam between i and j (beam1) with rigid connection at both i and j and a beam between j and k (beam2) with simple(hinge) connection at both j and k.
i-----------(1)------------j----------(2)-----------k
Basically I want rigid connection at the left side of node j and simple/hinge connection at the right side of the node j.
How many nodes should I define at node j ? (2 or 3) ?
I defined one node at i and 2 nodes at j and also 2 nodes at k and used equaldof command but I am not sure if it is correct!
simple/hinge connection
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Re: simple/hinge connection
Hi,
you should define 3 nodes at j node. So in the definition of the equaldof command, the middle node will be common for beam 1 and 2.
you should define 3 nodes at j node. So in the definition of the equaldof command, the middle node will be common for beam 1 and 2.
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- Posts: 84
- Joined: Tue Nov 07, 2017 7:47 am
- Location: University of Central Florida
Re: simple/hinge connection
I am not sure if I understand you correctly. If I define 3 nodes at j, how I can make sure the beam/column connection is rigid at the left side of the j and simple/hinge at right side of the j ?
Re: simple/hinge connection
In this case, the definition of 2 nodes in j is sufficient. However, with the three nodes, the above modeling can also be performed.