can't add cyclical load

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liuxing08
Posts: 14
Joined: Tue Sep 04, 2012 6:37 pm
Location: Tsinghua University

can't add cyclical load

Post by liuxing08 »

timeSeries Path 93 -dt 1 -filePath 93.txt
pattern Plain 93 93 {
load 93 1 0 0
}


I want to add cyclical load to my computational model, and my code is above. The profile 93.txt is like this "0 173.6481747 342.0201377 499.9999923 642.7876006 766.0444336 866.0253949 939.6926137 984.8077489 1000 984.8077582 939.692632 866.0254216 766.044468 642.7876416 500.0000387 342.0201881 173.6482275 5.35898E-05.........". But that didn't work. Does anybody know why?
fmk
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Posts: 5884
Joined: Fri Jun 11, 2004 2:33 pm
Location: UC Berkeley
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Re: can't add cyclical load

Post by fmk »

should work just fine. what happened and what is your analysis options.
liuxing08
Posts: 14
Joined: Tue Sep 04, 2012 6:37 pm
Location: Tsinghua University

Re: can't add cyclical load

Post by liuxing08 »

I have tried four types of analysis as followed:
1
constraints Transformation
test NormDispIncr 1e-3 50 1
algorithm Newton
numberer RCM
system SparseGEN
integrator Newmark 1.6 1.1025
analysis Transient
analyze 109 5

2
constraints Penalty 1e18 1e18
test NormDispIncr 1e-3 50 1
algorithm KrylovNewton
numberer RCM
system ProfileSPD
set nw 1.5
integrator Newmark $nw [expr pow($nw+0.5, 2)/4]
analysis VariableTransient
set startT [clock seconds]
analyze 109 5
set endT [clock seconds]

3
system SparseGEN
test NormDispIncr 1.0e-3 50 1
algorithm KrylovNewton
#constraints Penalty 1.e12 1.e12
constraints Transformation
set nw 1.5
#integrator Newmark $gamma [expr pow($gamma+0.5, 2)/4]
integrator HHT 0.7
rayleigh 0.25 0.0 0.1 0.0
analysis Transient

set startT [clock seconds]
analyze 109 5

4
numberer Plain
system ProfileSPD
test NormDispIncr 1.0e-3 50 1
algorithm KrylovNewton
constraints Penalty 1.e12 1.e12
set nw 1.5
#integrator Newmark $gamma [expr pow($gamma+0.5, 2)/4]
integrator HHT 0.7
rayleigh 0.25 0.0 0.1 0.0
analysis Transient

set startT [clock seconds]
analyze 109 5
fmk
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Posts: 5884
Joined: Fri Jun 11, 2004 2:33 pm
Location: UC Berkeley
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Re: can't add cyclical load

Post by fmk »

the dt in your analyze is 5 units, in your time series you are saying the points are 1 unit apart .. so you will be hitting every 5th point starting at the 6'th (as the first point in the time series is assumed to be time 0.0
yang
Posts: 1
Joined: Sat Jun 20, 2015 5:45 am

Re: can't add cyclical load

Post by yang »

Thank you. But now the sticking point is: with this method, the structure has no stress and displacement, which means invalid.
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